一个队伍长120M,A匀速(相对于大地)从队末走到队首,立刻返回,当回到队末时,队伍走了(匀速)288M,求A走的路程?
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偶来坐沙发了..-_-其实偶刚来过的..真是..哎..
物理..偶的天敌啊..天哪..恐怖..想着就恐怖…
以后表提到它了啊~~~~~~~~(只管沙发..舒服>_
设人速度为a,对速度为b.(a>b)
120/a+b[人从末到首所用时],
120/a-b[人从首到末所用时],
240a(2)/a(2)-b(2)[人走路程表达式1]
288a/b[人走路程表达式2]
上述两式相等,在化简6a(2)-5ab-6b(2)=0,(2a-3b)(3a+2b)=0.
得a=3/2b,代入人走路程表达式其一,等答案为:432
吃火锅了
厉害 我晕~~
桂冠太笨!
。。。。。。一做物理就想起周成金叔叔。。。
同意!!!桂冠太笨~~呵呵
432的答案错的。
不用算了,本来就不合逻辑。
本来我是沙发的,可是算了一个数字发上去,回头一想是错的,怕丢人,就拜托他给删了。。。
432是正确答案~~